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    Hey, I havent done trig/triangles for what seems like a long time and I have found all the angles in a triangle given all the lengths and now I have to find the area. I can't use 1/2bxh because I dont know the perpendicular height, so what do I use? Thanks.

    Ps. I realise this could be the most retarded question of the day but meh
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    (Original post by The Randy Panda)
    Hey, I havent done trig/triangles for what seems like a long time and I have found all the angles in a triangle given all the lengths and now I have to find the area. I can't use 1/2bxh because I dont know the perpendicular height, so what do I use? Thanks.

    Ps. I realise this could be the most retarded question of the day but meh
    Area= ab(sin(C)/2)

    Where a and b are lengths and C the angle opposite to length c.
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    (Original post by davidcy147)
    Area= ab(sin(C)/2)

    Where a and b are lengths and C the angle opposite to length c.
    this

    in the case of a right angled triangle, C = 90 degrees, so sin(C) = 1, so you get ab/2 as hte area of a right angled triangle
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    All done now, thanks
 
 
 
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