Merry Christmas Everybody!

Well, happy January sales when the time comes.

izvenyetie tavyu matt
chamon mo fo

differentiate: y = 4x^3 + 6x^2 - 2x + 8

dy/dx = 12x^2 + 12x - 2

differentiate: y = 4x^3 + 6x^2 - 2x + 8

dy/dx = 12x^2 + 12x - 2

what is this ^ symbol all about

ma la ge chou be de mei you er ze de shen jing bing.

mo fo

Asked for it!

ha what language is that

thank you please

you watch bo selecta

^ means "to the power of"

have a look on your calculator

you know what you should chnge the xmas day thing to give me presents day.

i dont blame ppl cause i too enjoy recieving lol

dy/dx = 12x^2 + 12x - 2
=>y = 4x^3 + 6x^2 - 2x + C
where C is the Christmas constant

lol That is a very good one! Mightly impressed...

proper bo I tell thee

Sarcasm is the sincerest form of flattery.

But what if you're a Christian and you believe in the birth of Jesus and give one another presents to celebrate his birth (even if he wasn't born on that day)?

No seriously, so impressed that you are going up on my rep list meepmeep!

dy/dx = 12x^2 + 12x - 2
=>y = 4x^3 + 6x^2 - 2x + C
where C is the Christmas constant

find the point of intersection of line: y = 3x + 6 and line y = 2x + 8.

eliminate y as both equations are equal to y, therefore:
3x + 6 = 2x + 8
x = 2

sub. x = 2 back into y = 3x + 6 to find y:
y = (3 * 2) + 6 = 12

therefore the point of interesection of the line y = 3x + 6 and the line y = 2x + 8 is: (2, 12)

I'd just like to wish everybody at UK Learning a Merry Christmas. Hope you all enjoy your presents.