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AT82
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#41
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#41
.... and there won't be snow in Manchester this Christmas time, where nothing ever grows, no pain or liver goes. Do they know its a reglious time at all?

Feed the mi---ind, let them know its a religous time....

Ok I shall shut the f**k up!
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GH
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#42
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#42
(Original post by amazingtrade)
.... and there won't be snow in Manchester this Christmas time, where nothing ever grows, no pain or liver goes. Do they know its a reglious time at all?

Feed the mi---ind, let them know its a religous time....

Ok I shall shut the f**k up!
That was a pretty good poem until the last bit
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meepmeep
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#43
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#43
(Original post by amazingtrade)
.... and there won't be snow in Manchester this Christmas time, where nothing ever grows, no pain or liver goes. Do they know its a reglious time at all?

Feed the mi---ind, let them know its a religous time....

Ok I shall shut the f**k up!
Please continue!
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LPK
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#44
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#44
anyone opened there presents yet?
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GH
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#45
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#45
(Original post by eric bischoff)
anyone opened there presents yet?
no, have you?
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piggsy_123
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#46
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#46
(Original post by meepmeep)
Oi! Stop trying to hijack my Christmas thread with maths! Go muck up your own!
solve the quadratic equation, leaving answers in surd form:
3x^2 + 6x + 2 = 0

using the quadratic equation: a = 3, b = 6, c = 2

x = [-6 (+/-) sq.root (36 - 4*3*2)] / 6
x = [-6 (+/-) sq.root (36 - 24)] / 6
x = [-6 (+/-) sq.root (8)] / 6
x = [-6 (+/-) sq.root (8)] / 6
x = [-6 (+/-) 2 sq.root 2] / 6
x = [-3 (+/-) sq.root 2] / 3

Therefore:

x = - [(3 + sq.root 2) / 3] OR x = - [(3 - sq.root 2) / 3]
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AT82
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#47
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#47
Silent Night
Holy ****e
All is rough
All is bleak
Round the muderers is a mugger and child
Sleep in prison ton--ight
Sleep in prison tonight.

__________

PS I am sorry this is so crap.
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meepmeep
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#48
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#48
(Original post by piggsy_123)
solve the quadratic equation, leaving answers in surd form:
3x^2 + 6x + 2 = 0

using the quadratic equation: a = 3, b = 6, c = 2

x = [-6 (+/-) sq.root (36 - 4*3*2)] / 6
x = [-6 (+/-) sq.root (36 - 24)] / 6
x = [-6 (+/-) sq.root (8)] / 6
x = [-6 (+/-) sq.root (8)] / 6
x = [-6 (+/-) 2 sq.root 2] / 6
x = [-3 (+/-) sq.root 2] / 3

Therefore:

x = - [(3 + sq.root 2) / 3] OR x = x = - [(3 - sq.root 2) / 3]
Well fine then. Merry Christmas to all, and to all a good night.
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LPK
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#49
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#49
(Original post by meepmeep)
Well fine then. Merry Christmas to all, and to all a good night.
good night bye
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Adhsur
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#50
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#50
Thanks, Merry Christmas!
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LPK
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#51
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#51
(Original post by Adhsur)
Thanks, Merry Christmas!
merry chrimbo
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viviki
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#52
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#52
Merry Christmas everyone!!

Now I'd better go to bed before the hangover sets in!
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LPK
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#53
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#53
(Original post by viviki)
Merry Christmas everyone!!

Now I'd better go to bed before the hangover sets in!
bye have a merry chrimbo

my 2,700th post
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pedy1986
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#54
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#54
MERRY CHRISTMAS

Just all remember

JESUS DID IT FOR THE CHICKS
Attached files
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LPK
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#55
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#55
(Original post by corey)
MERRY CHRISTMAS

Just all remember

JESUS DID IT FOR THE CHICKS
that is strange
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pedy1986
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#56
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#56
(Original post by eric bischoff)
that is strange
don't deny it!
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LPK
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#57
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#57
(Original post by corey)
don't deny it!
im not.Deny what?
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pedy1986
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#58
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#58
(Original post by eric bischoff)
im not.Deny what?
*shrugs*
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Egan1
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#59
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#59
(Original post by corey)
*shrugs*
Well, I'm off to bed now. Should give me enough sleep to get up before noon

Night all
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LPK
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#60
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#60
(Original post by Egan1)
Well, I'm off to bed now. Should give me enough sleep to get up before noon

Night all
good night
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