A rectangular garden of width w metres and length (w + 4)metres
The length of the garden's diagonal is d metres, so
d(squared)= 2w(squared) +8w + 16 ........after working out pythagora's
Given also that d must be at least twice as big as w,
show thar the maximum value of w can be expressed in the form
(a = b(square root)3)
Sorted it now. It's easy you just use the quadratic formula.
2 + 2root3