Two particles A and B, of mass mkg and 3 kg respectively, are connected by a light inextensible string. The particle A is held resting on a smooth fixed plane inclined at 30° to the horizontal. The string passes over a smooth pulley P fixed at the top of the plane. The portion AP of the string lies along a line of greatest slope of the plane and B hangs freely from the pulley, as shown in the figure m1.doc. The system is released from rest with B at a height of 0.25 m above horizontal ground. Immediately after release, B descends with an acceleration of 2/5 g. Given that A does not reach P, calculate
a) the tension in the string while B is descending,
b) the value of m.
i dont understand how to calculate part b. so far i have done :
For particle A going upwards : F=ma but i dont know what to minus from T T- ......= m x 2/5 g
for a) i got T=17.64N -->18 (2sf) which is correct