Join TSR now and get all your revision questions answeredSign up now

Draw a labelled diagram to show H-bonding between 2 molecules of liquid ammonia Watch

    • Thread Starter
    Offline

    0
    ReputationRep:
    Liquid ammonia, NH3, and water, H20, both show H-Bonding.


    So basically, i know how to draw it.. but erm could someone please clarify whether it's a or b:

    a) only link two NH3 via h-bonding...h20 molecule not relevant - so don't include.

    or

    b) link two NH3 using a water molecule.
    Offline

    3
    ReputationRep:
    (Original post by FoOtYdUdE)
    Liquid ammonia, NH3, and water, H20, both show H-Bonding.


    So basically, i know how to draw it.. but erm could someone please clarify whether it's a or b:

    a) only link two NH3 via h-bonding...h20 molecule not relevant - so don't include.

    or

    b) link two NH3 using a water molecule.
    Two NH3.
    • Thread Starter
    Offline

    0
    ReputationRep:
    (Original post by Kinkerz)
    Two NH3.
    so basically...a??

    aah, cheers.

    bdway,

    how do i suggest the formula for sodium chlorate (vii) ?? :confused:
    Offline

    3
    ReputationRep:
    (Original post by FoOtYdUdE)
    so basically...a??
    :yep:

    (Original post by FoOtYdUdE)
    bdway,

    how do i suggest the formula for sodium chlorate (vii) ?? :confused:
    Not sure.
    • Thread Starter
    Offline

    0
    ReputationRep:
    (Original post by Kinkerz)
    :yep:


    I'd go with NaClO3, but I may be wrong.
    it's NaCl04 butt i dunno y. oh nvm. thnxxx.
    Offline

    3
    ReputationRep:
    (Original post by FoOtYdUdE)
    it's NaCl04 butt i dunno y. oh nvm. thnxxx.
    At this point, do you need to know why?
    Offline

    3
    ReputationRep:
    If you're using oxidation states:

    O = -2
    Na = +1
    ---
    4(-2) + 1 = -7

    So the Cl must have an oxidation number of +7, hence your sodium chlorate (vii) ion.
    • Thread Starter
    Offline

    0
    ReputationRep:
    (Original post by Kinkerz)
    If you're using oxidation states:

    O = -2
    Na = +1
    ---
    4(-2) + 1 = -7

    So the Cl must have an oxidation number of +7, hence your sodium chlorate (vii) ion.
    genius!

    i get it!
    • Thread Starter
    Offline

    0
    ReputationRep:
    so basically if it was sodium chlorate (III) then the Cl would have an ox. no. of +3 ?? aaah and then the formula would be NaCl02 ??
    Offline

    3
    ReputationRep:
    (Original post by FoOtYdUdE)
    so basically if it was sodium chlorate (III) then the Cl would have an ox. no. of +3 ?? aaah and then the formula would be NaCl02 ??
    That'd be my approach, yes.
 
 
 
Poll
What is your favourite film genre?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Quick reply
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.