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    hey just wanted to see what you guys thought of my answer to this question...

    i get 0.282 kg for the mass of steel that must be contained in the steel brake drums.

    what do you guys think?

    -Sarah
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    I think you're a few orders of magnitude out, when you consider the size of the average drum break. 200g really isn't a lot of steel.

    Have a look at your units, maybe.
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    hmm.. i was thinking that i might have done something like that... can anyone confirm what the actual answer is?
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    A quick guess makes me think about 28kg maybe?

    Would work it out, but I'm at work.

    Whoops!
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    lol, fair enough :P

    Thanks morals_officer!
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    no no, i know what i did :P, forgot to square v in the KE formula! :P
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    Get 6.26kg in tha end?

    dKE = 1/2 mv^2 [d meaning delta]
    dKE = 1/2 * 1400 * (80000/(60*60))^2
    dQ = dKE
    dQ = 345, 679

    m = dQ/(c * dT)
    m = 345,679/((0.11*4.184*1000)* 120)
    m = 6.26kg
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    yeah i got 6.26 , lol good ol square of the velocity
 
 
 
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