This discussion is closed.
KaosLisa
Badges: 0
#1
Report Thread starter 16 years ago
#1
Could someone explain to me how to do these two optimisation questions.

1)
An open toppped box has height h cm and square base of side xcm.

The box has capacity Vcm^3. The area of its external surface consisting of its horizontal base and four vertical faces is Acm^2

a) Find expressions for V and A in terms of x and h.

b) It is given that A = 3000

i) Show that V=750x - 1/4x^3

ii) Find the positive value of x for which DV/dx = 0 giving your answer in surd form.

2)
Small trays are to be made from rectangular pieces of card. Each piece of card is 8cm by 5cm and the tray is formed by removing squaress of side xcm from each corner and folding the remaining card along the dashed lines.

a) Explain why 0 < x < 2.5

b) Show that the volume Vcm^3, of a tray is given by
V = 4x^3 - 26x^2 + 40x

c) Find the value of x for which dV/dx = 0

d) Calculate the greatest possible volume of a tray
0
mikesgt2
Badges: 0
Rep:
?
#2
Report 16 years ago
#2
1)
a) You should be able to do these.
b)
(i) Substitute 3000 into the equation you found for A in part a) in order to find h in terms of x. Then substitute this expression for h into your equation for V. Rearrange to give the required result.
(ii) Differentiate V wrt x, set to zero, solve quadratic.
0
GH
Badges: 13
Rep:
?
#3
Report 16 years ago
#3
(Original post by mikesgt2)
1)
a) You should be able to do these.
b)
(i) Substitute 3000 into the equation you found for A in part a) in order to find h in terms of x. Then substitute this expression for h into your equation for V. Rearrange to give the required result.
(ii) Differentiate V wrt x, set to zero, solve quadratic.
Interesting...

For b): I get...

x^2 + 4hx = 3000

And I was wondering how to solve for x...
0
mikesgt2
Badges: 0
Rep:
?
#4
Report 16 years ago
#4
(Original post by 2776)
Interesting...

For b): I get...

x^2 + 4hx = 3000

And I was wondering how to solve for x...
4hx = 3000 - x^2
h = ( 3000 - x^2 )/4x = 750/x - x/4

Sub this into the equation for V...

V = hx^2 = ( 750/x - x/4 )x^2 = 750x - (x^3)/4
0
GH
Badges: 13
Rep:
?
#5
Report 16 years ago
#5
(Original post by mikesgt2)
4hx = 3000 - x^2
h = ( 3000 - x^2 )/4x = 750/x - x/4

Sub this into the equation for V...

V = hx^2 = ( 750/x - x/4 )x^2 = 750x - (x^3)/4
Thats really clever...never thought of doing it that way.
0
mikesgt2
Badges: 0
Rep:
?
#6
Report 16 years ago
#6
(Original post by 2776 2)
Thats really clever...never thought of doing it that way.
Are you the same person as 2776?
0
GH
Badges: 13
Rep:
?
#7
Report 16 years ago
#7
(Original post by mikesgt2)
Are you the same person as 2776?
Yes. Or more aptly, 2776 is the same person as me.
0
prince_capri
Badges: 2
Rep:
?
#8
Report 16 years ago
#8
(Original post by 2776 2)
Yes. Or more aptly, 2776 is the same person as me.
why did u change ur screen name ???
0
X
new posts
Back
to top
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

How are you feeling ahead of results day?

Very Confident (12)
8.57%
Confident (18)
12.86%
Indifferent (25)
17.86%
Unsure (38)
27.14%
Worried (47)
33.57%

Watched Threads

View All