Please help me with the following question:
"1.20 g of potassium iodate(V) are dissolved and made up to 250cm^3 with distilled water in a standard flask. 25 cm^3 of this solution are taken and added to an excess of potassium iodide solution and a small amount of dilute sulphuric acid, then titrated with sodium thiosulphate in the burette. A few drops of starch solution are added when the solution turns a pale straw colour and the end point is taken as the appearance of a permanent blue-black colour in solution. Calculate the concentration of the sodium thiosulphate solution given that 27.6 cm^3 are required to reach the end point and given the following equations:
Iodate(V) ions and iodide ions in acidic solution:
IO3^- (aq) + 5I^- (aq) + 6H^+ (aq) --> 3I2 (aq) + 3H2O (l)
Thiosulphate ions and iodine:
2S2O3^2- (aq) + I2 (aq) --> 2I^- (aq) + S4O6^2- (aq)"
Please include steps to the solution, or else I won't understand.
Thanks