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2 aqa decision questions watch

    • Thread Starter

    if someone could help me with these tow questions i would be so grateful, i absolutely have no idea how to do these
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    Ha. I did this paper yesterday!

    First question is your graph theory:
    If there's 5 vertices, the minimum spanning tree will have 4 edges won't it? So the minimum value for the min. span tree has to include the 4 smallest values that can link all 5 vertices.
    The maximum must include the biggest and smallest seeing as the graph will have to have all 8 edges in.
    The way I did the last part, was to find four values that add up to 53, sketch those, then work out where the other values can fit around that so that the minimum spanning tree remains 53.

    What part of the second question do you need hep with?
    • Thread Starter

    ooooo thanks that makes sense
    and the whole of question 7 ;/ i can normally do them questions but when they through inequalities in there i just get confused!

    You know that C is the closest point to A. So: AC < (everywhere else A can go). And since it's telling you to compare AC and AB you get:
    2x - 4 < x + 6

    You do this is a similar manner, just consider AD and AE. So you'll end up with:
    2x - 4 < 3x - 7 and
    2x - 4 < 4x - 14
    So solve these for x.

    This is done in a similar manner as before. The question tells you that CD < CB or CE (CA we don't know). So you then get:
    2x - 1 < 3x - 7
    2x - 1 < x + 8
    Again, solve these for x.

    From the inequalities you have, you should be easily be able to solve this - given that x is an integer.

    This should be really easy now that you know x.
    • Thread Starter

    it actually makes sense now! Thanks so much x
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