For sinusoidal current the mean power over full cycle is 1/2 peak power Is this true? Watch

Freerider101
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#1
Report Thread starter 8 years ago
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For a sinusoidal current is the mean power over full cycle is half the peak power? This is a quote from a textbook however I thought that with sinusoidal graphs you always divided by root 2 for mean power?
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Stonebridge
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Average Power is IrmsVrms and the rms I is Io/√2 and rms V is Vo/√2
Average Power is VoIo/2
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Freerider101
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(Original post by Stonebridge)
Average Power is IrmsVrms and the rms I is Io/√2 and rms V is Vo/√2
Average Power is VoIo/2
Okay cheers so would Irms²=½Io²
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Stonebridge
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(Original post by Freerider101)
Okay cheers so would Irms²=½Io²
Irms = Io/√2
Irms² = Io/√2 x Io/√2 = Io²/2

So, yes
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