# Log Laws. Help!Watch

#1
Hi!

This is part of a C4 integration problem. I'm having problem from here onwards...

The answer is supposed to be :

Can someone tell me where I'm going wrong. Thanks.
0
8 years ago
#2
19/3 - 2ln3 + 2ln2
19/3 - (2ln3 - 2ln2)
19/3 - 2(ln3 - ln2)
19/3 - 2(ln(3/2))
19/3 - 2ln(3/2)
thats how you get the answer, cant see where youve gone wrong though
0
8 years ago
#3
Well technically both are correct, I'm just not sure how they got to theirs.

2ln(2/3) = -2ln(3/2)

-2ln(3/2) = 2ln((3/2)^-1)

= +2ln(2/3)
0
8 years ago
#4

19 + 2ln(2/3) = 19 + 2ln[(3/2)^-1] = 19 - 2ln(3/2)
0
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