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Jaziek
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#1
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Ok, this is from the Jan 03 paper. I think I'm on the right track, I get a couple of simultaneous equations, but I'm not quite sure how to solve them, or if I've got the right ones.

Any help, from the start would be most helpful please.
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Mr ABC
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post your equations please
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Jaziek
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Tsin20+R=1.5gcos30

Tcos20=1.5gsin30+F
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Mr ABC
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(Original post by Jaziek)
Tsin20+R=1.5gcos30

Tcos20=1.5gsin30+F
They are correct, you know that F=R/3, as the coeff of friction is 1/3

then eliminate the R's from the equations (by subtracting one from the other)
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Jaziek
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(Original post by Mr ABC)
They are correct, you know that F=R/3, as the coeff of friction is 1/3

then eliminate the R's from the equations (by subtracting one from the other)
so

 Tsin20 + 3Tcos20 = 1.5gcos30 + 4.5gsin30

?
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Mr ABC
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(Original post by Jaziek)
so

 Tsin20 + 3Tcos20 = 1.5gcos30 + 4.5gsin30

?
Yes, then  T(sin20 + 3cos20) = 1.5gcos30 + 4.5gsin30

then divide both sides by  (sin20 + 3cos20)

Voila
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Jaziek
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(Original post by Mr ABC)
Yes, then  T(sin20 + 3cos20) = 1.5gcos30 + 4.5gsin30

then divide both sides by  (sin20 + 3cos20)

Voila
got it.

T=11.

thanks.
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