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    o/n/03 question 3

    Can help?

    I really appreciate any answers....
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    you need to work out the kinetic energy at the lowest point of the small circle ( although the particle is higher than that when it begins this small circular motion ).

    then recall that for completion of a circle the string must remain taut at the top... for this to happen it can be shown that the speed at the lowest point of the ( small ) circle must be not less than the square root of 5gr where r is the radius of the small circle

    good luck

    the bear

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    Can show the full solution? Thanks a lot
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    Attached is a full handwritten solution to question 3.

    I cannot say the solution is 100% error-proof.

    However I do not understand from B to C (Refer to the solution attached) , the mechanical energy at C, it has r-0.5r cos(alpha)+0.5r
    as the height.

    Can explain?
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  1. File Type: pdf Question 3 Solution.pdf (538.1 KB, 96 views)
 
 
 
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Updated: May 21, 2010

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