# Higher Physics Question - HELP!!Watch

#1
Hi,

Can anyone explain how you are supposed to do Q14 in the multiple choice part of the 2006 Higher Physics paper?

Thanks!
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8 years ago
#2
What's the question???
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#3
There's a diagram to go with it that I can't copy in. Theres a source of light and its reflecting off a bit of metal and also going straight on and the two beams meet to produce a maxima (it doesn't tell you what order). It tells you the distance from the source of light to the maxima directly, and asks you to calculate what the indirect distance (via the surface reflecting the light) is.
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8 years ago
#4
interesting question, would be great if i could see actually..... if not then i am sorry, you're gonna have to wait for someone who does this paper!!
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8 years ago
#5
Genral rule is to look at the path differecne

This sounds like a variation on Lloyds mirror. (look it up) There is a 90 degree phase change on reflection

so you get maxima when the path diff is (n + 0.5) x wavelength

Cant do much more without the question!
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8 years ago
#6
(Original post by nat_1606)
Hi,

Can anyone explain how you are supposed to do Q14 in the multiple choice part of the 2006 Higher Physics paper?

Thanks!
As constructive interference occurs, the path difference must be (400+28n)mm, the only answer which fits this is D at (400+28x2)
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