Lorentz transformations: time dilationWatch

#1
If I want to find the measured proper time interval between two events in some moving frame S' (at speed v) where the two events have no spacial seperation, what do I need to sub into a Lorentz transformation of the form

(where a ' means the interval in S' and no dash is in another frame S)

I can show time dilation using the transformation from the frame S:

since which gives the familiar time dilation formula.

but using the other transformation I get confused.
0
8 years ago
#2
(Original post by hai2410)
If I want to find the measured proper time interval between two events in some moving frame S' (at speed v) where the two events have no spacial seperation, what do I need to sub into a Lorentz transformation of the form

(where a ' means the interval in S' and no dash is in another frame S)

I can show time dilation using the transformation from the frame S:

since which gives the familiar time dilation formula.

but using the other transformation I get confused.
Whatever is. Anyways, why do you want to do that, it's much easier using the other formula...
0
#3
(Original post by TableChair)
Whatever is. Anyways, why do you want to do that, it's much easier using the other formula...
My bad, two events 'A' and 'B' then the AB subscript means between those two.

and I merely want to see that they both give the same answer... and why, well, because i'm weird like that.
0
8 years ago
#4
(Original post by hai2410)
My bad, two events 'A' and 'B' then the AB subscript means between those two.

and I merely want to see that they both give the same answer... and why, well, because i'm weird like that.

I understand that, but you should be able to think of an equation for it. Hint, you know v and you want to get rid of delta x and replace it with a delta t...

Haha, that's a good trait.
0
#5
(Original post by TableChair)
I understand that, but you should be able to think of an equation for it. Hint, you know v and you want to get rid of delta x and replace it with a delta t...

Haha, that's a good trait.
Excellent. Works a treat. Cheers
0
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