# Takng the average mean & var of two sample distributionsWatch

#1
Say one distribution, n = 50, mean = 2.5, standard dev = 1.5
second distribution, n = 25, mean = 3.0, standard dev = 1.8

I need to find a mean of the two distributions. So the mean of the mean is (2.5+3)/2 = 2.75

But how would I do this for the standard dev?

(1.5^2/rt 50 + 1.8^2/rt 25)/2 to find the average variance?
0
8 years ago
#2
i don't think they want you to take the average of the two means ( this only works if the two groups have equal numbers of items ).

instead you find the two group totals... 2.5 * 50 and 3.0 * 25... add them together to get the grand total .... then divide by the total number of items in the two groups.

for the standard deviations you have to figure out the two values of from the standard deviation formula... then add them together & put the result back in, together with the appropriate values of and n

the bear

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