M1 Question (particles on an inclined plane) Watch

dumb maths student
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Report Thread starter 8 years ago
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http://www.srepapmaxeeeerf.org/A%20L...%202008-01.pdf

Q4b) the only perpendicular force i can see is 6gcos30.

according to the mark scheme, there's also 49sinx ? by looking at the 49 force acting on the particle, 49sinx isn't perpendicular, but even if it was, it's pointing the other direction, so why is the calculation for R: 49sinx + 6gcos30?

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roar558
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49sinx is the component of the force acting on the particle perpendicular to the surface, it's acting in the same direction as the component of the weight, 6gcos30, so the total force acting perpendicular to the plane is 49sinx+6gcos30
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