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    Hi guys couple questions on math paper can't do can someone show a step by step analysis?

    A is the point (4,-3) and B is the point (-1,9)

    calculate AB... which was 13
    Find MP AB which was (1.5,3)

    Find equation of line through (1,3) which is parallel to AB, giving yuor answer in the form ax+by+c A,b,c are integers


    NEXT..

    Point P on the curve y=kx^1/2 has x coordinate 4. Normal to the curve at P is parallel to the line 2x+3y=0....(6)

    Find K

    thanks all
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    ok i think for first answer i got equation -2x-y+5=0 is this correct??
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    1) all you need is the gradient AB. y-y1=m(x-x1)
    2)find the gradient of the line 2x+3y=0
    find dy/dx of kx^1/2 where x=4
    the gradient of that line where x=4 ... well, its perpendicular to the line 2x+3y=0. what does that tell you?
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    (Original post by ashton.alfred)
    ok i think for first answer i got equation -2x-y+5=0 is this correct??
    Well done...do you want a gold star or chocolate bar? How on earth does this help the poster understand anything other than your attempt at a core 1 question?

    To the OP

    What is the 6 in here?

    Point P on the curve y=kx^1/2 has x coordinate 4. Normal to the curve at P is parallel to the line 2x+3y=0....(6)
    As for the question

    (i) are you happy differentiation that?
    (ii) finding the corresponding y coordinate?
    (iii) ok on appreciating the difference between normal and tangent?
    iv) Ok on subbing that into a linear equation?
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    (Original post by LJbrowning)
    Well done...do you want a gold star or chocolate bar? How on earth does this help the poster understand anything other than your attempt at a core 1 question?

    To the OP

    What is the 6 in here?



    As for the question

    (i) are you happy differentiation that?
    (ii) finding the corresponding y coordinate?
    (iii) ok on appreciating the difference between normal and tangent?
    iv) Ok on subbing that into a linear equation?
    That was the poster :facepalm:
 
 
 
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