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    A particle has velocity (6t+1)i + (3t-5)j
    Find the value of t for which the speed of the particle is at its minimum

    Many thanks!

    ps the answer is t = 1/5
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    you have been given the horizontal and vertical components of velocity, can you see how drawing a triangle might help you?
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    (Original post by Rubgish)
    you have been given the horizontal and vertical components of velocity, can you see how drawing a triangle might help you?
    no please elaborate
    thank you
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    your missing out part of the question....

    most likely the accleration or ssomething
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    (Original post by snoopyx)
    no please elaborate
    thank you
    Well, the horizontal and vertical components of velocity are at right angles to each other, so to find the speed, you can use pythagoras on them. (hor vel)^2 + (vert vel)^2 = (speed)^2 This should give you a quadratic equation for speed in terms of t which you can find the minimum of.
 
 
 
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