M1 help please Watch

snoopyx
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#1
Report Thread starter 8 years ago
#1
If the distance between two particles is given by: d^2 = (2t – 5)^2 + (t – 5)^2
find the value of t for which the two particles are closest
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noobie93
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#2
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Is there more information given with the question?

You'd want to multiply out the bracket first though.
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Rohit93
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#3
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I guess you can just make each bracket equal 0 so you'd get t = 5/2 and t=5
not sure if this is right though =/
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mjtriggs
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(Original post by Rohit93)
I guess you can just make each bracket equal 0 so you'd get t = 5/2 and t=5
not sure if this is right though =/
I'm not sure if this is correct, there should be some more information...
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anshul95
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#5
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You've got a choice:
1)Multiply out the brakets and complete the square to find the turning point of the resulting quadratic.
2) Multiply out the brackets, differentiate the expression and make the derivative =0.
3) As above except instead of multiplying out the brakets use the chain rule to differentiate the expression(if you know it its tonnes quicker)
Personally I like 3) though I always check my answer with 2) and then 1)
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