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    I have to draw 6 structural isomers for C6H14O. So I put the 6 Cs in but there are only 12Hs. I am confused becasue I thought there would be 14 Hs. So are my diagrams correct, with 12 Hs?

    And...is this the name for this chemical...3-ethylbutan-1-al or is it 3-dimethylbutan-1-al?
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    (Original post by galadriel100)
    I have to draw 6 structural isomers for C6H14O. So I put the 6 Cs in but there are only 12Hs. I am confused becasue I thought there would be 14 Hs. So are my diagrams correct, with 12 Hs?

    And...is this the name for this chemical...3-ethylbutan-1-al or is it 3-dimethylbutan-1-al?
    You have drawn C6H12O and the isomer you have drawn is actually 3-methylpentan-1-al (note the longest carbon chain in your isomer is 5 carbons long so it is based on pentanal)

    Actually though, the compound you have been asked for does not have any C=O double bonds as this decreases the 14 hydrogens to 12.
    Try alcohols or ethers - both of these can give the molecular formula given.
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    hexan-1-ol
    hexan-2-ol
    hexan-3-ol
    2-methylpentan-1-ol
    2,3dimethylbutan-2-ol
    3-methylpentan-2-ol

    There, six, hope that's okay. Try drawing these and i'll check them for you. Should be good practice for you.
 
 
 
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