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Binomial Expansion Core 2
11
For the binomial expansion in ascending powers of x of (1 +1/4x)^n
where n is an
integer and n ≥ 2,
(a) find and simplify the first three terms, (3)
(b) find the value of n for which the coefficient of x is equal to the coefficient of x^2. (3)
Thats the question, please can someone help me with part b i have no idea!
where n is an
integer and n ≥ 2,
(a) find and simplify the first three terms, (3)
(b) find the value of n for which the coefficient of x is equal to the coefficient of x^2. (3)
Thats the question, please can someone help me with part b i have no idea!
Reply 1
stanmoor
For the binomial expansion in ascending powers of x of (1 +1/4x)^n
where n is an
integer and n ≥ 2,
(a) find and simplify the first three terms, (3)
(b) find the value of n for which the coefficient of x is equal to the coefficient of x^2. (3)
Thats the question, please can someone help me with part b i have no idea!
where n is an
integer and n ≥ 2,
(a) find and simplify the first three terms, (3)
(b) find the value of n for which the coefficient of x is equal to the coefficient of x^2. (3)
Thats the question, please can someone help me with part b i have no idea!
You need to consider expressing the binomial coefficients in factorial notation. At the moment i'm assuming you've got terms for part (i) in the form .
Could you post your expansion of the first three terms so I can help you further.
Reply 2
stanmoor
OP
11
yep
in part a) i got 1+1/4nx + (n ncr 2) 1/16x^2
but then to find n arent you meant to do ... n!/2!(n-2) != x by all the numbers below it ??
in part a) i got 1+1/4nx + (n ncr 2) 1/16x^2
but then to find n arent you meant to do ... n!/2!(n-2) != x by all the numbers below it ??
Reply 3
stanmoor
OP
11
ahh dont worry about it i've done it ! 
thanks anyway
thanks anywayReply 4
how do u actually do this question
Reply 5
I am really confused
Reply 6
16
question is better written as (1 + x/4)^n
this should help ... ?
this should help ... ?
Original post by omi1666
I am really confused
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