balancing redox equations Watch

ashleyb123
Badges: 2
Rep:
?
#1
Report Thread starter 9 years ago
#1
Balance the half-equation for the reduction of dichromate(VI) ions.
Cr2O72– + ......H+ + ..... e− → ..... Cr3+ + ..... H2O

I got:
Cr2O72– + 7H+ + 4e− → 2Cr3+ + 3.5H2O

which is completely wrong...
the correct answer is:
Cr2O72- + 14H+ + 6e- → 2Cr3+ + 7H2O

how would you approach this question, and how can i get that answer?

hopefully this should be my last chem question today..:p:
many thanks
1
reply
CHEM1STRY
Badges: 11
Rep:
?
#2
Report 9 years ago
#2
(Original post by ashleyb123)
Balance the half-equation for the reduction of dichromate(VI) ions.
Cr2O72– + ......H+ + ..... e− → ..... Cr3+ + ..... H2O

I got:
Cr2O72– + 7H+ + 4e− → 2Cr3+ + 3.5H2O

which is completely wrong...
the correct answer is:
Cr2O72- + 14H+ + 6e- → 2Cr3+ + 7H2O

how would you approach this question, and how can i get that answer?

hopefully this should be my last chem question today..:p:
many thanks
Cr2O7 2- ==> Cr3+ balancing the atoms gives

Cr2O7 2- ==> 2Cr3+ now add waters to the RHS to balance oxygens

Cr2O7 2- ==> 7H2O + 2Cr3+ and add hydrogens to LHS to balance 7H2O

14H+ + Cr2O7 2- ==> 7H2O + 2Cr3+ and then add the electrons, we have a 6+ charge on the RHS and a 12+ charge on the LHS so we need to take six off the LHS so add 6 electrons

6e- + 14H+ + Cr2O7 2- ==> 7H2O + 2Cr3+
0
reply
ashleyb123
Badges: 2
Rep:
?
#3
Report Thread starter 9 years ago
#3
(Original post by CHEM1STRY)
Cr2O7 2- ==> Cr3+ balancing the atoms gives

Cr2O7 2- ==> 2Cr3+ now add waters to the RHS to balance oxygens

Cr2O7 2- ==> 7H2O + 2Cr3+ and add hydrogens to LHS to balance 7H2O

14H+ + Cr2O7 2- ==> 7H2O + 2Cr3+ and then add the electrons, we have a 6+ charge on the RHS and a 12+ charge on the LHS so we need to take six off the LHS so add 6 electrons

6e- + 14H+ + Cr2O7 2- ==> 7H2O + 2Cr3+
awesome thanks very much !!
0
reply
Chemmi
Badges: 2
Rep:
?
#4
Report 3 years ago
#4
If reduction has happened why did this equation start with cr3+?
Isn't that only if it's lost electrons? ?
0
reply
charco
Badges: 17
Rep:
?
#5
Report 3 years ago
#5
(Original post by Chemmi)
If reduction has happened why did this equation start with cr3+?
Isn't that only if it's lost electrons? ?
Reduction is addition of electrons (OILRIG)

The equation ENDS with Cr3+
0
reply
akramsid
Badges: 4
Rep:
?
#6
Report 11 months ago
#6
I know this is 8 years late, but it will help me anyways

Its all about balancing.

First you have to balance the Cr
Because it is Cr2 on the LHS it will be 2Cr on the RHS
this means the charge will be 2- to 6+
As there are 7 oxygen's, the other side must have 7H2O in order to also have 7 oxygens with a neutral charge as 2 H+ balances 1 O-2.
Then that means we have 14 H+ which needs to be added onto the other side.
Finally balance the electrons.
6+ charge on the RHS
12+ charge on the LHS
that means the LHS needs to add 6 electrons which have a negative charge. +6e- to balance the everything out.

I am doing my a-levels now, so plz dont hate that this is a late response.
1
reply
X

Quick Reply

Attached files
Write a reply...
Reply
new posts

All the exam results help you need

909

people online now

225,530

students helped last year

University open days

  • University of Dundee
    Undergraduate Open Day Undergraduate
    Mon, 26 Aug '19
  • University of Aberdeen
    General Open Day Undergraduate
    Tue, 27 Aug '19
  • Norwich University of the Arts
    Postgraduate (MA) Open Day Postgraduate
    Sat, 31 Aug '19

How are you feeling about GCSE Results Day?

Hopeful (213)
12.72%
Excited (151)
9.02%
Worried (303)
18.1%
Terrified (374)
22.34%
Meh (155)
9.26%
Confused (37)
2.21%
Putting on a brave face (229)
13.68%
Impatient (212)
12.66%

Watched Threads

View All