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Mr M
OCR (not OCR MEI) FP1 Answers June 2010

6

(ii) Shade region (2 marks)

8
(iii) Does not converge as sqrt of infinity = infinity (1 mark)



Thanks a lot that is great! Two things:

For the shaded regeion where were we supposed to shade? I shaded inside the circle, between Re(z)=3 and Re(z)=6. Wasn't too sure on that!

And for the one marker on whether it converges, do you think I would get the mark for just saying that as n increases the result can get infinitely big/there is no limit on it's value?

Cheers!
Reply 161
What quadratic did u start with for number 7?
Mr M, what do you think the UMS boundaries will be?

Also for question 4, did the argument have to be in radians?
Reply 163
For question 3 I put

1/6n(4n +2)(2n-1)=0

I forgot to take the 2 out as well to make it 1/3n(2n+1)...
I lose a mark for that, right?
Reply 164
Got about 57... hopefully. I need an A in this so much :/
Reply 166
1/3n(2n-1)(2n+1) could surely be "2/3n(n+1)(2n-0.5)"....how many marks do you think would be dropped for that :frown:
Reply 167
Was the starting equation for the roots question on question 7 x^2 - 2kx + k? :s-smilie:
Reply 168
Mr M
OCR (not OCR MEI) FP1 Answers June 2010


1. Prove by induction (5 marks)


2. I will edit this later to make it look nice (can't remember how to do matrices in LaTeX and my school network is blocking the TSR wiki!):

(i) (-7) (2 marks)

(ii) 2 x 2 matrix top row -7 - 20 bottom row 11 -20 (4 marks)


3. n(2n1)(2n+1)3\frac{n(2n-1)(2n+1)}{3} (6 marks)


4. (i) modulus = 13 argument = 1.18 (4 marks)

(ii) 118527i85\frac{-11}{85} - \frac{27i}{85} (3 marks)


5. (a) 2 x 2 matrix top row 0 1 bottom row 1 0 (2 marks)

(b) (i) Stretch in x direction scale factor 5

(ii) Rotation clockwise about the origin by pi/3 (2 marks)


6 (i) (a) Circle centre 3 - 4i radius 5 (2 marks)

(b) Vertical line with Re(z)=3 (2 marks)

(ii) Shade region (2 marks)


7 x24kx+4k=0x^2 -4kx + 4k = 0 (7 marks)


8 (i) Show (2 marks)

(ii) n+1+n+2122\frac{\sqrt{n+1} + \sqrt {n+2} - 1 - \sqrt{2}}{2} (6 marks)

(iii) Does not converge as sqrt of infinity = infinity (1 mark)


9 (i) a(a1)a(a-1) (3 marks)

(ii) (a) Inconsistent

(b) Consistent but no unique solution

(c) Consistent with unique solution

10 (i) z=2+iz = 2 + i (5 marks)

(ii) Show (1 mark)

(iii) w=2iw = 2 -i (5 marks)


Shout if you disagree with something as I haven't checked my work yet.




Thanks Mr M

Two things: 1) What do you think the grade boundaries would be
2) Have you got the answers for Core 4?

Thanks again
Mr M
(ii) Rotation clockwise about the origin by pi/3 (2 marks)


Monsieur M, I wrote two answers to this question
1) Clockwise rotation of 60 about the origin
which is 2) Anti Clockwise rotation of -60 about the origin.
Will I get the mark or not? :frown:
I got all of 10 wrong because of one silly error right at the beginning of part i :sad: :frown: but not terrible I reckon, still got college ti resit :smile:
Mr M
OCR (not OCR MEI) FP1 Answers June 2010
6 (i) (a) Circle centre 3 - 4i radius 5 (2 marks)

(b) Vertical line with Re(z)=3 (2 marks)

(ii) Shade region (2 marks)



Mr M are you sure the centre is 3-4i, I can't remember the question but I distinctly remember drawing a circle of centre 3+4i going through O with radius of 5. Correct me if I'm wrong.

everything else looks ok, I can safely say I've got at least 90 UMS
I've made some ridiculously silly mistakes. I'm actually fairly upset about that. I didn't read the question properly. :frown: I really hope it's going to be an A above 55 raw marks. :frown:
payday5950
Mr M are you sure the centre is 3-4i, I can't remember the question but I distinctly remember drawing a circle of centre 3+4i going through O with radius of 5. Correct me if I'm wrong.

everything else looks ok, I can safely say I've got at least 90 UMS


The modulus given was:

│z-3+4i│ which can be written as │z-(3-4i)│ so the centre of the circle is 3 - 4i (I think) :p:

Congrats on your UMS!
Reply 174
payday5950
Mr M are you sure the centre is 3-4i, I can't remember the question but I distinctly remember drawing a circle of centre 3+4i going through O with radius of 5. Correct me if I'm wrong.

everything else looks ok, I can safely say I've got at least 90 UMS


Yep it was - can't remember exactly why though, something to do with:

z - (3 + 4i) = z - 3 - 4i
Reply 175
I got 100 UMS in Jan 2010 does that mean I got 100% or something else?
Jing_jing
Pfft, Helen, were you not listening during Locke's many many many hours of note dictating on it? Jokes, loves you really XD If detA = 0, then it's either inconsistent or has an infinite amount of solutions.


What a stupid question! Of course I was listening.... just, forgot it, that's all :p:
payday5950
Mr M are you sure the centre is 3-4i, I can't remember the question but I distinctly remember drawing a circle of centre 3+4i going through O with radius of 5. Correct me if I'm wrong.

everything else looks ok, I can safely say I've got at least 90 UMS


yes it is 3 - 4i
nikita_atikin
Monsieur M, I wrote two answers to this question
1) Clockwise rotation of 60 about the origin
which is 2) Anti Clockwise rotation of -60 about the origin.
Will I get the mark or not? :frown:


Yes that's ok.
Revolution is my Name
Indeed; that one you had to come up with for June 09 was absolutely hellish.


I did that paper last year, we'd all done really well on the practice papers and then we got out of the exam and were like "WTF was THAT?" My friend couldn't do the conjecture and lost all the marks.

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