Right, I'll give this a go.
The complex they give you is a Cu2+ ion (still octahedral) with 2 water molecules still attached and to of these [en] ligands which attach in two places each (hence bidentate ... 2 teeth). If you can't picture this then let me know and I'll post a diagram.
The oxidation state of the Cu is still +2 (hasn't changed)
The coordination number is 6 (hasn't changed ... still ligands attached in 6 places, it just happens that 2 of the ligands are attached in 2 places each!)
Colour change:
This is to do with the splitting of the d orbitals - have you done this yet? The reason the colour changes is because the ligands change, and this changes the energy difference between the orbitals so the delta value changes and the energy of light (and hence colour) absorbed, changes.
Equation:
ligand displacement reaction:
(sorry I'm not bothering with subscripts / superscripts!)
[Cu(H2O)6]2+ + 2en ---> [Cu(H2O)2(en)2]2+ + 4H2O
If you still don't understand any of it, let me know.