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A2 Chemistry Transition Metals

Hi, could anyone help me with these Transition metal questions please ... I'm really confused about all these complexes. :confused:

The bidentate ligand 1,2-diaminoethane, NH2CH2CH2NH2, reacts with an aqueous soultion of copper (II) sulphate to give a deep blue solution containing the ion [Cu(NH2CH2CH2NH2)2(H20)2]2+.

What's the oxidation state and coordination number of Cu in this ion? (Coordination number 4?)

What causes the colour change in this reaction? (Change in coordination number?)

Write an equation for the reaction. You may use "en" for NH2CH2CH2NH2. (I have no idea about this)

Can anyone help, please?

Reply 1

Right, I'll give this a go.

The complex they give you is a Cu2+ ion (still octahedral) with 2 water molecules still attached and to of these [en] ligands which attach in two places each (hence bidentate ... 2 teeth). If you can't picture this then let me know and I'll post a diagram.

The oxidation state of the Cu is still +2 (hasn't changed)
The coordination number is 6 (hasn't changed ... still ligands attached in 6 places, it just happens that 2 of the ligands are attached in 2 places each!)

Colour change:
This is to do with the splitting of the d orbitals - have you done this yet? The reason the colour changes is because the ligands change, and this changes the energy difference between the orbitals so the delta value changes and the energy of light (and hence colour) absorbed, changes.

Equation:
ligand displacement reaction:
(sorry I'm not bothering with subscripts / superscripts!)

[Cu(H2O)6]2+ + 2en ---> [Cu(H2O)2(en)2]2+ + 4H2O

If you still don't understand any of it, let me know.

Reply 2

That's great, thanks. We haven't been through the details on the origin or colour quite yet, just that a change of ligand causes a change of colour.

A few things I was unsure about: when you have a complex like this [Co(NH3)6]Cl3 where are the Cl atoms positioned? Same for CoCl3.5NH3 -I'm not sure what the complex looks like (coordination number 6 and oxidation state 2+).

Reply 3

Velouria
That's great, thanks. We haven't been through the details on the origin or colour quite yet, just that a change of ligand causes a change of colour.

A few things I was unsure about: when you have a complex like this [Co(NH3)6]Cl3 where are the Cl atoms positioned? Same for CoCl3.5NH3 -I'm not sure what the complex looks like (coordination number 6 and oxidation state 2+).


The Cl- ions are not ligands in that compound ... they are the anions to go with the Co ions. In aqueous phase they will be free floating Cl- ions.

Reply 4

Ah okay, but the question says:

Suggest a structural formula for CoCl3.5NH3 which indicates the number of ligands around the cobalt ion.

Would this just be [Co(NH3)5]Cl3 or would it be [Co(NH3)5(H20)]Cl3 because it was a reaction of aqueous cobalt chloride with an excess of aqueous ammonia...?

Reply 5

Only the chlorides can be balancing ions, so the five ammonia molecules must be ligands. This leaves one place available in the octahedral complex that must be occupied by one of the chlorides. The overall charge on the complex ion must then be 2+

[Co(NH3)5Cl]Cl2

in which the [Co(NH3)5Cl]2+ ion is balanced by two chloride ions Cl-

Cobalt pentaamminechloro III ion?

Reply 6

The structural formula for CoCl3.5NH3 will may not be octahedral shaped.....it could be a trigonal bipyramid shape with 3 Cl- counter ions....

[Co(NH3)5].3Cl .....i.e cobalt in it's +3 oxidation state

Reply 7

Sorry Xskater, it's octahedral. Transition metals of the first row do not form 5-coordinate complexes...