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The thermal energy required to convert ice at -0ºC to water at +0ºC is equal to the mass of water multiplied by the specific latent heat of fusion of ice. It follows that:
E = 330,000 x 0.65
E = 214500 Joules
E = 215kJ
The formula E = mθ∂T, where m is the mass in kilograms, θ is the specific heat capacity and ∂T is the temperature change, still applies in the question above. However, since 0ºC is a critical temperature for water. i.e. the point at which is condenses and freezes, the temperature change, ∂T is negligable and does not need to be considered in the above calculation.
E = 330,000 x 0.65
E = 214500 Joules
E = 215kJ
The formula E = mθ∂T, where m is the mass in kilograms, θ is the specific heat capacity and ∂T is the temperature change, still applies in the question above. However, since 0ºC is a critical temperature for water. i.e. the point at which is condenses and freezes, the temperature change, ∂T is negligable and does not need to be considered in the above calculation.
Sezkin
I'm kinda stuck on this question for physic below:
The specific latent heat of fusion (melting) of ice is 330,000 Jkg-1.
What is the energy needed to melt 0.65kg of ice?
Any help appreciated.
Thanks
The specific latent heat of fusion (melting) of ice is 330,000 Jkg-1.
What is the energy needed to melt 0.65kg of ice?
Any help appreciated.
Thanks
These LINKS might be useful. It is a very large site and covers from easy to very advanced.
http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/heat.html#c1
http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/phase2.html#c1
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