# I Need Help Desperatly With My Maths!!!Watch

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#1
Hi
Can anyone explain to me how to solve a simualtaneous equation? I need to know for my mock maths gcse tomorrow!
Thank-you!
0
16 years ago
#2
ask me a question then i'll go through the stages.
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#3
(Original post by 2776)
ask me a question then i'll go through the stages.

ok thanks:

x2 - 4y2 = 24
x + 2y = 6
0
16 years ago
#4
Hi
Can anyone explain to me how to solve a simualtaneous equation? I need to know for my mock maths gcse tomorrow!
Thank-you!

chad are you doing calc or non? there are no simultanoues equations on the calc...if i can remember correctly i did it two days ago

but you need to know surds, vectors and algebra **** well...
0
16 years ago
#5
ok thanks:

x2 - 4y2 = 24
x + 2y = 6

how can you have 4y2?
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#6
(Original post by ThornsnRoses)
chad are you doing calc or non? there are no simultanoues equations on the calc...if i can remember correctly i did it two days ago

but you need to know surds, vectors and algebra **** well...

nah, im doing no-calc first
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16 years ago
#7
(Original post by ThornsnRoses)
how can you have 4y2?
and i realise that is of now help...

what you do is you take away one equation from the other so that you get no xs or no ys...and then you solve the xs...
with the solved xs you subsitute the xs with numbers and then solve y....i hope that helps
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#8
(Original post by ThornsnRoses)
how can you have 4y2?

sorry, when i said 4y2 and x2, i meant 4y^2 and x^2
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16 years ago
#9
nah, im doing no-calc first

no similtaneous equations...edexcel right?

but i warn you the paper is not easy...
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#10
(Original post by ThornsnRoses)
and i realise that is of now help...

what you do is you take away one equation from the other so that you get no xs or no ys...and then you solve the xs...
with the solved xs you subsitute the xs with numbers and then solve y....i hope that helps

cool. Thank-you and to everyone who helped!
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#11
(Original post by ThornsnRoses)
no similtaneous equations...edexcel right?

but i warn you the paper is not easy...

oh great! Im rubbish at maths anyway, but i wanted to do good.
0
16 years ago
#12
ok thanks:

x2 - 4y2 = 24
x + 2y = 6
OK, sorry for the delay forgot all about that.

x^2-4y^2=24

x+2y=6

therefore x=6-2y

subsitute that in for x^2 in first equation.

36 - 12y + 4y^2 -4y^2 = 24

12 = 12y

y=1
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#13
(Original post by 2776)
OK, sorry for the delay forgot all about that.

x^2-4y^2=24

x+2y=6

therefore x=6-2y

subsitute that in for x^2 in first equation.

36 - 12y + 4y^2 -4y^2 = 24

12 = 12y

y=1

Sorry, where does the 36 and the 12y come from?
btw, i have been given the answers and they are
x =5
y = 0.5
0
16 years ago
#14
Sorry, where does the 36 and the 12y come from?
btw, i have been given the answers and they are
x =5
y = 0.5
yes, did it in my head sorry, should be 24y
0
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