Can anyone explain to me how to solve a simualtaneous equation? I need to know for my mock maths gcse tomorrow.
ive replied on the other identical thread youve posted.
repeating youself is not conduicive to recieving help. and i would help if i could but im rubbish at maths and hate it.
Rearrange one of the equations to make x or y the subject:
x + 2y = 6
x = 6-2y
Now we know that x is the same as 6-2y so in the other equation we can substitute x for 6-2y:
x2 - 4y2 = 24
(6 - 2y)2 - 4y2 = 24
now multiply out the brackets and rearrange a bit:
36 - 24y + 4y2 -4y2 =24
24y = 36 -24 = 12
y = 12/24 = 1/2
now we can substitue 1/2 for y in one of the original equations:
x + 2*1/2 = 6
x = 6-1 = 5
nah, i dont find em easy, but my strength isnt exactly maths. neawy thanks for the help everyone!
Sorry to ask again. I know this is gonna sound dumb but could you explain again, cos I dont understand where you get the 36 from. Also the answers are
x = 5
y = 0.5
I just don't know how to get there.