# Maths: P1 Differentiation Help PlesaeWatch

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#1
Hi,

Please could somebody help me with the following, preferably showing the steps gone through to achieve the answer:

By the way... sq. means 'square root', / means divide by, and ^ means to the power of.

Find the gradient of the curve with equation y=f(x) at the point where x=a when:

a) f(x) = sq.(12x).............a = sq.3

b) f(x) = x-4/x^2..............a = -2
0
16 years ago
#2
Hi,

Please could somebody help me with the following, preferably showing the steps gone through to achieve the answer:

By the way... sq. means 'square root', / means divide by, and ^ means to the power of.

Find the gradient of the curve with equation y=f(x) at the point where x=a when:

a) f(x) = sq.(12x).............a = sq.3

b) f(x) = x-4/x^2..............a = -2
a) (12x)^1/2 differentiates to 1/2(12)^1/2. (x)^-(1/2) - plug in your values and you're done.

b) x - 4x^-2 differentiates to 1 + 8x^-3 - just plug in values again.
0
16 years ago
#3
hey,
these are the steps you should take to get the answer:
1. differentiate y=f(x)
2. since they are asking for the gradient of the curve at a particular point it means that it is the gradient of the tangent to the curve which means gradient of tangent(gradient at that point in the curve)= dy/dx.
3. so use the value of "x" given to you and substitute it into the derivative to get the gradient(m). that will be your answer.
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