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# C3 Differentiation watch

1. Can someone help me differentiate ? I get but apparently the answer is .
2. You should be using the product rule on the first term since it's a product of and .
3. If y = e^ax

Then dy/dx = ae^ax

For individual functions.

For y=f(x)g(x), you should use the product rule - dy/dx = f'xg(x) + g'xf(x)

4. hey everyone how would i differentiate 1over ln 1/2x ? i now that you have to do 1over 1/2 x but then what?
Thanks
5. (Original post by Stach462)
hey everyone how would i differentiate 1over ln 1/2x ? i now that you have to do 1over 1/2 x but then what?
Thanks
You should probably make a new thread for a different question.
In any case, stick brackets in your question or I can't tell what it is you want to differentiate!
6. (Original post by ViralRiver)
Can someone help me differentiate ? I get but apparently the answer is .
let u = 3x-1
chain rule.

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