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    Can someone help me differentiate 3xe^{3x}-e^{3x}? I get 9xe^{3x}-3e^{3x} but apparently the answer is 9xe^{3x}+3e^{3x}-3e^{3x}.
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    You should be using the product rule on the first term since it's a product of 3x and e^{3x}.
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    If y = e^ax

    Then dy/dx = ae^ax

    For individual functions.

    For y=f(x)g(x), you should use the product rule - dy/dx = f'xg(x) + g'xf(x)

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    hey everyone how would i differentiate 1over ln 1/2x ? i now that you have to do 1over 1/2 x but then what?
    Thanks
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    (Original post by Stach462)
    hey everyone how would i differentiate 1over ln 1/2x ? i now that you have to do 1over 1/2 x but then what?
    Thanks
    You should probably make a new thread for a different question.
    In any case, stick brackets in your question or I can't tell what it is you want to differentiate! :p:
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    (Original post by ViralRiver)
    Can someone help me differentiate ? I get but apparently the answer is .
    let u = 3x-1
    chain rule.
 
 
 
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