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    Hello

    Can anyone tell me the answers to these two questions? Workings out are essential aswell. Much appreciated.
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    The first one is a right angled triangle so you use Pythagoras Theroem.

    Second one is 16000/7.

    Im sure you can work it out.
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    We can't give you answers on the forum, but we can help you try to work it out (for yourself).

    For the first question, do you know the pythagoras theorem? The longest side is opposite the right angle... so you need to rearrange it.
    For the second question, how many seconds are in one minute? 60! Therefore, how many metres does the bee fly per minute? It'll be 60 x 7...
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    for the first one, you use pythagoras' theorem, a^2 + b^2 = c^2

    c is the hypotenuse (the longest side), so rearrange, to find a^2:

    a^2 = c^2 - b^2
    = 13^2 - 6^2
    = 169 - 36
    = 133
    a = square root of 133 (round to 3 significant figures)

    for the second one, use the formula: speed = distance / time


    and rearrange to give time = distance / speed

    so time = 16,000 / 7

    and then work that out (that gives the number of seconds)

    then divide the answer by 60, as there are 60 seconds in a minute.

    Round the answer to 3 s. f.
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    For the first one, would the answer happen to be 14.3??
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    (Original post by Jackb95)
    For the first one, would the answer happen to be 14.3??
    Nope. you need to find a^2 so rearrange the formula a^2+b^2=c^2

    to get a^2=c^2-b^2 so a^2 is 169-36 = 133 a is going to be the qaure root of 133 to 3 S.F.
 
 
 
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