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# Vectors watch

1. An aeroplane flies due North 100km/hr whilst it climbs vertically upwrads at 5.0/m/s. Calculate the velocity of the aeroplane.

So i drew a triangle and converted the 100km/hr into m/s =27.7

then i did pythagos to find the resultant vector to get 28.1 m/s. Is this correct?
2. If this is correct how would i go about finding the displacment of the plane after 10 seconds. As i havnt been given the time...
3. The method is correct. So the answer should be ok if you have done the maths correctly.
The displacement after 10s is just this velocity times 10s.
Do they also want the direction?
4. (Original post by Stonebridge)
The method is correct. So the answer should be ok if you have done the maths correctly.
The displacement after 10s is just this velocity times 10s.
Do they also want the direction?
Ye i worked it out thanks . And I Pressume so althought it doesnt specify but as its a vector it has to have a direction.
5. If they haven't asked for the direction I wouldn't worry about it.
Having said that, if you are interested, it would be best to express it as the angle/direction the plane flies "upwards" relative to the horizontal. That is, in one second it flies 27.7 m due north and 5 m upwards. The angle would be tan^-1 (5/27.7)

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Updated: September 27, 2010
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