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    hey,

    so i don't understand how does the PH works when the H+ concentration is beyond 1x10^-8 to even more diluted.. because if you take the PH= -log[1x10^-8] = 8, which is basic so it couldn't be right.. i know i am just confused at the moment, so someone please explain to me

    thanks
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    never mind.. i just got it
 
 
 
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Updated: September 25, 2010

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