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# Integrating secx method help watch

1. (Original post by Mr M)
Have a break then. You don't need to do any of this. Just learn the integral of sec^2 x with respect to x is tan x + a constant.
No I want to get this. Now you I take it you made du/ u^2 +1

into

(u^-2 +1^-1)du

Integrating that I see

(-u^-1) +(1^-1)(u) +c
2. (Original post by Unknown?)
No I want to get this. Now you I take it you made du/ u^2 +1

into

(u^-2 +1^-1)du
No I made . I just added one and subtracted one. It is just a maths trick to split up the improper fraction as I didn't know whether you knew polynomial division or partial fractions.
3. I thought this said interesting sex method help
4. (Original post by Mr M)
No I made . I just added one and subtracted one. It is just a maths trick to split up the improper fraction as I didn't know whether you knew polynomial division or partial fractions.
I'm not talking about that part I'm referring to the integration of

du/u^2 +1
5. (Original post by Unknown?)
I'm not talking about that part I'm referring to the integration of

du/u^2 +1
Oh no. I think you just did something mathematically horrible.

6. (Original post by Mr M)
Oh no. I think you just did something mathematically horrible.

Ah right. Well so far all I'm is getting tanx -1.

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Updated: September 26, 2010
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