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    Could someone please tell me how to go about finding the stationary points of a curve with formula y=x^2(12-4x-3x^2) ?

    I'd appreciate any help..
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    Multiply out, differentiate, factorize.
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    A stationary point on the curve occurs when the gradient of the curve is 0. You can find out the gradient of a curve by differentiating it.

    So, if the gradient of the curve is dy/dx, and the gradient must be 0 at a stationery point, then dy/dx=0 at that point.

    Hopefully you know how to differentiate an equation, once you have expanded it to give you:

    y=12x^2-4x^3-3x^4
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    Thanks for the help, I have it now.
 
 
 
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