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    Find the exact value of cot(arcsin (-sqaure root of 3 / 2))
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    (Original post by ballerina girl)
    Find the exact value of cot(arcsin (-sqaure root of 3 / 2))
    Take care of the (arcsin (-sqaure root of 3 / 2) first, which will be one of your standard degree values. Then that will be with your cot.
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    find the value of arcsin(/sqrt 3/2), then do...1/tan(answr). If u need the answer, let me know.
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    Well firstly you can rewrite  arcsin(-\frac{\sqrt3}{2}) as  sinX = \frac{\sqrt3}{2} . So then you can think, what sine of an angle gives this value? 60 degrees gives you what you are looking for but its negative so it will have to be -60.

    Now you have  \frac{1}{tan60} . tan60 = sqrt3 so your answer will be one over that.

    I think they expect you to know the values of sin, cos, tan of 30, 45 and 60. If you draw some right angled triangles you can figure it out. They're in the pics below.
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Updated: September 27, 2010
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