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    basically, we got given this equation
    H2O2 + 2I^- + 2H^+ >> 2H2O + I2
    because we cant measure the rate of this equation because it happens so fast, we introduce a slow step to slow down the rate so we can measure the rate and compare it to different concentrations of H2O and H2O2. We add some Na2S2O4 to slow it down.
    I'm presuming r=rate, the question is, how would you carry out experiments to prove r=0...?
    If you need more information to answer the question tell me what it is and I will try to respond with what information is useful.
    One last question, If I were to draw a rate against concentration graph. Why would the line of best fit have to pass through the origin? not including 0 order reactions
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    (Original post by Eloades11)
    basically, we got given this equation
    H2O2 + 2I^- + 2H^+ >> 2H2O + I2
    because we cant measure the rate of this equation because it happens so fast, we introduce a slow step to slow down the rate so we can measure the rate and compare it to different concentrations of H2O and H2O2. We add some Na2S2O4 to slow it down.
    I'm presuming r=rate, the question is, how would you carry out experiments to prove r=0...?
    If you need more information to answer the question tell me what it is and I will try to respond with what information is useful.
    One last question, If I were to draw a rate against concentration graph. Why would the line of best fit have to pass through the origin? not including 0 order reactions

    if r= rate and rate = 0 the reaction never happens...

    ..think about it!
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    (Original post by charco)
    if r= rate and rate = 0 the reaction never happens...

    ..think about it!
    carry out the experiment so there is no rate? im confused
 
 
 
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