C3, Somebody Save Me... (equation of normal etc etc...)

$y = \frac{5}{2(3x - 1)^{4}}$ yea?

yeayah how did you do that!?

Use the quotient rule to differentiate it with regards to x.

Can you see where you go from here?

how did you do that!?

See http://www.thestudentroom.co.uk/wiki/LaTex

Edit: Too slow

That can never be true

thanks every1! i clocked just now that i have to differentiate, but im having trouble applying the rule, the 5 on the top is doing my nut in, we havent been taight this yet :/ could anybosy shw me the differentiation process or at least the result... Thanks people, truly

Have you differentiated (ax+b)^n using the chain rule?

This is the same thing with a 2.5 (5/2) infront.

y = k(ax+b)^n

dy/dx = ...

yeayah how did you do that!?

LaTeX, it's a system for typing mathematical expressions. Very, VERY useful See here for more info.

Back to the question :P How could you re-write this so that it would help make it into something easier?

EDIT: Should read other replies to thread before replying to quotes! :P

It is worth just knowing how to write down the answer for the derivative of a linear function raised to a power.

$y = k (ax + b)^n$

$\frac{dy}{dx} = kan (ax + b)^{(n-1)}$

Oh i see, yh it was the k that was doing me in, we hadnt worked on examples with "k" involved, so i take dy/dx is now -30(3x-1)^-5??

Oh i see, yh it was the k that was doing me in, we hadnt worked on examples with "k" involved, so i take dy/dx is now -30(3x-1)^-5??