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    So if you have this:

    2HI = H2 + I2

    Is it possible to get a rate equation from it? Or does it always have to be derived from doing an experiment?
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    rate equation involves reactant(s)....what do you think?
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    As far as I know, it has to be done via experiment.

    You don't know how fast the HI bonds are 'breaking', nor how fast the H2/I2 bonds are forming.
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    (Original post by boromir9111)
    rate equation involves reactant(s)....what do you think?
    ...I don't know. My teacher said something about having to do experiments, but I don't know whether there is a way of getting a rate equation from a balanced equation.
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    You have to do experiments in order to find out the relationship....have you covered first order, second order reactions, etc?

    edit - sorry, I didn't mean to come off as a "nob", I am truly sorry for that
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    AnonyMatt is right; the rate equation can only be found by experimentation.
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    (Original post by AnonyMatt)
    As far as I know, it has to be done via experiment.

    You don't know how fast the HI bonds are 'breaking', nor how fast the H2/I2 bonds are forming.
    (Original post by raymanh)
    AnonyMatt is right; the rate equation can only be found by experimentation.

    Thank you


    (Original post by boromir9111)
    You have to do experiments in order to find out the relationship....have you covered first order, second order reactions, etc?
    We're doing first order and second order reactions at the moment, seeing how to find them on graphs. I just wasn't sure if there was a way of deriving it from the equation as we're only a few weeks into the new course.
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    (Original post by LadyLoveDisdain)
    Thank you




    We're doing first order and second order reactions at the moment, seeing how to find them on graphs. I just wasn't sure if there was a way of deriving it from the equation as we're only a few weeks into the new course.
    Oh, don't worry about that as of now, your teacher will go over examples with you. All you need to know now is how to interpret it "graphically" cause that is the gateway to the questions in past exam papers that will no doubt come up!
 
 
 
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