A current-carrying conductor placed at right angles to a uniform magnetic field, experiences a force of 4.7 x 10^-3 N. Determine the force on the wire when the current in the wire is increased by a factor of 3.0
I HAVE NO IDEA!
I think if I were to just times by 3 it would be wrong as it's not taking into account B and L, therefore I am not sure how to work this out. Please help.
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CAN SOMEONE PLEASE PLEASE PLEASE HELP current-carrying conductor placed at right angl watch
- Thread Starter
- 30-09-2010 23:17
- 30-09-2010 23:34
B is magnetic field strength, which i think is constant here, as is L
F = BIL
I = F/BL
if I is multiplied by 3 so if (F/BL)
B and L are constant, so F is multiplied by 3Last edited by theths; 30-09-2010 at 23:37.