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# Quick Differentiation help please... watch

1. Differentiate this by using the chain rule:
5/3-2x

How do you work this out? So the chain rule is: dy/dx = (dy/du) (du/dx)
u=3-2x so y=..erm
2. (Original post by Scott3142)
This is not differentiable by the chain rule, quotient rule is needed, presuming its 5/(3-2x) rather than (5/3) - 2x.
What? It is differentiable using the chain rule. [In fact the chain rule makes more sense than the quotient rule here since the numerator is constant.]

OP: If you let then . Differentiating (wrt x) and (wrt u) is C1 stuff, so you shouldn't have any problems here!
3. Yeh I know, sorry, I misread the question .
4. (Original post by nuodai)
What? It is differentiable using the chain rule. [In fact the chain rule makes more sense than the quotient rule here since the numerator is constant.]

OP: If you let then . Differentiating (wrt x) and (wrt u) is C1 stuff, so you shouldn't have any problems here!
Thanks! I get that one now
last question, sorry :/
How do you do differentiate this one then? (again, its chain rule)
3/(x+1)^2
so let u=x+1 and y is = ? :/
5. (Original post by Neuron_16)
Thanks! I get that one now
last question, sorry :/
How do you do differentiate this one then? (again, its chain rule)
3/(x+1)^2
so let u=x+1 and y is = ? :/
Just replace 'x+1' with 'u'.

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Updated: October 2, 2010
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