Points P(-5,-2) Q(-1,6) R(7,7) and S(3,-1) are the verticles of a parallelogram.
M is the midpoint of PQ at (-3,2)
MS is perpendicular to PQ
How do I find out the area of the parallelogram? I know that it can reshape to be a square and that I could possibly use triangle rules. But im unsure in these graph terms.
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- Thread Starter
- 02-10-2010 16:53
- 02-10-2010 17:13
I find doing a rough sketch helps. Find the base by doing the length between 2 points. The height I think will be the mid point of PQ, then find the length of that , though I'm not sure about the perpendicular part .