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# Finding the real part of a complex number... watch

1. Hello, could someone help me solve this question please,

Thanks.
2. Re=1
3. What have you done and where are you stuck?
4. Firstly, simplify the complex number so you get it in the form z = a + bi where a and b are real numbers. Re(z) = a. When simplifying, remember that i^2 = -1.
5. (Original post by ziedj)
What have you done and where are you stuck?
It's just the fact that there are 2 real parts which is confusing me.

For instance, I'd know that . But at there are two 'complex numbers' as it were, I'm left a little confuzzled.
6. (Original post by §01)
Firstly, simplify the complex number so you get it in the form z = a + bi where a and b are real numbers. Re(z) = a. When simplifying, remember that i^2 = -1.
Oh, I'm such an idiot.

Thanks.
7. (Original post by RamocitoMorales)
It's just the fact that there are 2 real parts which is confusing me.

For instance, I'd know that . But at there are two 'complex numbers' as it were, I'm left a little confuzzled.
Expand the brackets first, remembering that i^2 = -1 (which is real).
8. (Original post by RamocitoMorales)
Oh, I'm such an idiot.

Thanks.
9. (Original post by Dededex)

10. (Original post by RamocitoMorales)

Good good

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