Turn on thread page Beta
    • Thread Starter
    Offline

    0
    ReputationRep:
    A shelf support is made of wood (with its cross section shown in the diagram)

    The shape of the curved edge of the shelf support is modelled by the equation:

    8y= (2x-3)^3 for -1</= y </= 1

    I'll try and give you data from the diagram:

    1) Curve Crosses the x-axis when x = 3/2
    2) Intersects y= 1 when x = 5/2
    3) Shaded area is in the positve x quadrants only

    a) Find the point where the curve intersects y= -1 .
    Offline

    10
    ReputationRep:
    (Original post by Mambo No. 5)
    A shelf support is made of wood (with its cross section shown in the diagram)

    The shape of the curved edge of the shelf support is modelled by the equation:

    8y= (2x-3)^3 for -1</= y </= 1

    I'll try and give you data from the diagram:

    1) Curve Crosses the x-axis when x = 3/2
    2) Intersects y= 1 when x = 5/2
    3) Shaded area is in the positve x quadrants only

    a) Find the point where the curve intersects y= -1 .
    Dont you just have to substitute y=-1 into main equation and find value of x???
    • Thread Starter
    Offline

    0
    ReputationRep:
    (Original post by cazzy-joe)
    Dont you just have to substitute y=-1 into main equation and find value of x???
    Yes but I'm finding it a bit complicated with the 8y = f(x) ....... when I divide it by 8 (to simplify it a bit), it's far too complex too find x. Or is there another method?
    Offline

    10
    ReputationRep:
    (Original post by Mambo No. 5)
    Yes but I'm finding it a bit complicated with the 8y = f(x) ....... when I divide it by 8 (to simplify it a bit), it's far too complex too find x. Or is there another method?
    I dont think there is any other method.
    And you have to substitute value of 'y' to find 'x'. I think you have substitute x=-1 instead y=-1. Try again..

    I think they ask you to find x when y=-1 because it is the limits to find area (because range for y is -1</= y </= 1)
    • Study Helper
    Offline

    15
    Study Helper
    (Original post by Mambo No. 5)
    Yes but I'm finding it a bit complicated with the 8y = f(x) ....... when I divide it by 8 (to simplify it a bit), it's far too complex too find x. Or is there another method?
    If you substitute the value for y, then you wil have "-8" on the left hand side, which is a perfect cube. The cube root has only one value.
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: October 3, 2010
The home of Results and Clearing

1,202

people online now

1,567,000

students helped last year

University open days

  1. University of Buckingham
    Postgraduate Open Evening Postgraduate
    Thu, 23 Aug '18
  2. University of Glasgow
    All Subjects Undergraduate
    Tue, 28 Aug '18
  3. University of Aberdeen
    Undergraduate Open Day Undergraduate
    Tue, 28 Aug '18
Poll
How are you feeling about GCSE results day?
Useful resources

Make your revision easier

Maths

Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

Equations

How to use LaTex

Writing equations the easy way

Student revising

Study habits of A* students

Top tips from students who have already aced their exams

Study Planner

Create your own Study Planner

Never miss a deadline again

Polling station sign

Thinking about a maths degree?

Chat with other maths applicants

Can you help? Study help unanswered threads

Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.