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# C2 - Integration Question. watch

1. A shelf support is made of wood (with its cross section shown in the diagram)

The shape of the curved edge of the shelf support is modelled by the equation:

8y= (2x-3)^3 for -1</= y </= 1

I'll try and give you data from the diagram:

1) Curve Crosses the x-axis when x = 3/2
2) Intersects y= 1 when x = 5/2

a) Find the point where the curve intersects y= -1 .
2. (Original post by Mambo No. 5)
A shelf support is made of wood (with its cross section shown in the diagram)

The shape of the curved edge of the shelf support is modelled by the equation:

8y= (2x-3)^3 for -1</= y </= 1

I'll try and give you data from the diagram:

1) Curve Crosses the x-axis when x = 3/2
2) Intersects y= 1 when x = 5/2

a) Find the point where the curve intersects y= -1 .
Dont you just have to substitute y=-1 into main equation and find value of x???
3. (Original post by cazzy-joe)
Dont you just have to substitute y=-1 into main equation and find value of x???
Yes but I'm finding it a bit complicated with the 8y = f(x) ....... when I divide it by 8 (to simplify it a bit), it's far too complex too find x. Or is there another method?
4. (Original post by Mambo No. 5)
Yes but I'm finding it a bit complicated with the 8y = f(x) ....... when I divide it by 8 (to simplify it a bit), it's far too complex too find x. Or is there another method?
I dont think there is any other method.
And you have to substitute value of 'y' to find 'x'. I think you have substitute x=-1 instead y=-1. Try again..

I think they ask you to find x when y=-1 because it is the limits to find area (because range for y is -1</= y </= 1)
5. (Original post by Mambo No. 5)
Yes but I'm finding it a bit complicated with the 8y = f(x) ....... when I divide it by 8 (to simplify it a bit), it's far too complex too find x. Or is there another method?
If you substitute the value for y, then you wil have "-8" on the left hand side, which is a perfect cube. The cube root has only one value.

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