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solve cosec²?+1=3cot?

This is what i have got so far?

I think I have done it wrong. More in a moment

I think this is now correct. pic 16

Pic 17 seems to show that one of my solutions is wrong... Am now checking..

This is what i have got so far?

I think I have done it wrong. More in a moment

I think this is now correct. pic 16

Pic 17 seems to show that one of my solutions is wrong... Am now checking..

Scroll to see replies

turtle2

Oh thanks. I actually have another Q: cot?=1-cosec²?, 0«?«2?

Here is my solution to the question that has already been answered.

( In case ppl are confused the original question was sent to me as a PM but I could not upload to image... so had to post)

steve2005

Here is my solution to the question that has already been answered.

( In case ppl are confused the original question was sent to me as a PM but I could not upload to image... so had to post)

( In case ppl are confused the original question was sent to me as a PM but I could not upload to image... so had to post)

But you've worked out: 1 + cot²θ = cosec²θ

turtle wanted to work out cotθ = 1-cosecθ²

I think ...

Ricki

But you've worked out: 1 + cot²? = cosec²?

turtle wanted to work out cot? = 1-cosec?²

I think ...

turtle wanted to work out cot? = 1-cosec?²

I think ...

I don't know... I get so confused... turtle if I have answered the wrong question ... please say so.

--------------

Ricki

But you've worked out: 1 + cot²? = cosec²?

turtle wanted to work out cot? = 1-cosec?²

I think ...

turtle wanted to work out cot? = 1-cosec?²

I think ...

Ricki on my computer theta does not appear in my messages but it does appear in yours. The theta disappears to be replaced by a question mark in the quoted part.... even if a type nothing.

Do you know how to correct this. I use the option Enhanced Mode...and not Guided Mode. I have experimented in the past but ....

Testing ? ? µ ? ? ½ µ

steve2005

Ricki on my computer theta does not appear in my messages but it does appear in yours. The theta disappears to be replaced by a question mark in the quoted part.... even if a type nothing.

Do you know how to correct this. I use the option Enhanced Mode...and not Guided Mode. I have experimented in the past but ....

Do you know how to correct this. I use the option Enhanced Mode...and not Guided Mode. I have experimented in the past but ....

I'm using the guided mode, the default. I've experienced this problem before, I'm not sure how it is corrected though ...

--------------

BCHL85

well, I think you need to download javascript.

I've got the javascript.

Ricki

I'm using the guided mode, the default. I've experienced this problem before, I'm not sure how it is corrected though ...

--------------

I've got the javascript.

--------------

I've got the javascript.

cos? I have just typed cos theta using Guided Mode. To get theta I clicked on theta in the menu . I am now doing pi ?

steve2005

cos? I have just typed cos theta using Guided Mode. To get theta I clicked on theta in the menu . I am now doing pi ?

It can be that your browser does not support the use of these symbols.

Or .. you need to download Java ... from ... http://java.sun.com/j2se/1.4.2/download.html

Ricki

It can be that your browser does not support the use of these symbols.

Or .. you need to download Java ... from ... http://java.sun.com/j2se/1.4.2/download.html

Or .. you need to download Java ... from ... http://java.sun.com/j2se/1.4.2/download.html

But, how come I can see your symbols but not the ones I produce. Question: In my last post there should be a symbol for theta .... can you see the symbol or do you see a question mark

turtle2

f) (secθ-cosθ )²=tanθ-sin²θ , 0«θ«π

f) (secθ-cosθ )²=tanθ-sin²θ

.. (1/cosθ - cosθ )² = sinθ/cosθ - sin²θ

... 1/cos²θ - 2 + cos²θ = sinθ/cosθ - sin²θ

... 1/cos²θ - 2 + cos²θ = sinθ/cosθ - (1-cos²θ )

... 1/cos²θ + cos²θ - 2 = cos²θ + sinθ/cosθ - 1

... 1/cos²θ + cos²θ - 2 - cos²θ - sinθ/cosθ + 1 = 0

... sec²θ - tanθ - 1 = 0

sub sec²θ = tan²θ + 1, following the identity:

... tan²θ + 1 - tanθ - 1 = 0

... tan²θ - tanθ = 0

... tanθ - 1 = 0

... tanθ = 1

... θ = arctan[1], θ = π/4 etc.

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can someone please explain what principle domain is and why the answer is a not c?Maths

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