A solution of B was prepared by dissolving 4.32g of B in water and making the solution up to 250cm^3.
A titration was carried out with 25cm^-3 of the solution of B, that was neutralised by exactly 23.20cm^3 of 0.200 HCl
1mol of B reacts with 1mol HCl. Calculate the Mr of B and suggest its identity
23.20cm^3(HCl) = 0.0232dm^3(HCl)
Moles(HCl) = 0.200 x 0.0232 = 0.00464.
Therefore 0.0464g = 1mol of B
whoa, where did this come from?
You have only taken 25ml from the original solution and found the moles of HCl that this reacts with. If you have all 250 ml it would react with 0.00464 x 10 moles HCl = 0.0464
You are told that it's a 1:1 reaction, so the moles of base = 0.0464
AND you know the mass of this number of moles = 4.32g
So the RMM = 4.32/0.0464 = 93.1
So, same answer, although I don't see how you've got there...
You have only taken 25ml from the original solution and found the moles of HCl that this reacts with. If you have all 250 ml it would react with 0.00464 x 10 moles HCl = 0.0464
You are told that it's a 1:1 reaction, so the moles of base = 0.0464
AND you know the mass of this number of moles = 4.32g
So the RMM = 4.32/0.0464 = 93.1
So, same answer, although I don't see how you've got there...
I have timesed by ten
Any idea on the base it could be? And what about the first question?
You have only taken 25ml from the original solution and found the moles of HCl that this reacts with. If you have all 250 ml it would react with 0.00464 x 10 moles HCl = 0.0464
You are told that it's a 1:1 reaction, so the moles of base = 0.0464
AND you know the mass of this number of moles = 4.32g
So the RMM = 4.32/0.0464 = 93.1
So, same answer, although I don't see how you've got there...
Also is it normal to find this bit of chemistry confusing? Its just Im good at maths but seem to struggle with the calculations bit