Hi everyone. I don't know what to do to answer this question. help me plz.
"In some hot countries, tea is served in a pot with a glass 2/3 full of ice. The boiling tea is poured into the glass to fill it. Estimate the remperature of the resulting drink.
Specific latent heat of fusion for ice = 3.3 x 10^5 J/kg
Specific heat capacity of water: 4200
Thermal physics question Watch
- Thread Starter
- 28-11-2010 13:41
- 28-11-2010 14:38
You need to estimate only, so assume that the mass of ice is about 2/3 and the water 1/3 (of the total mass) when the glass is full.
Let the mass of the water = m and the ice = 2m.
Initial temperature of tea = 100 deg C
Let final temperature =T [the answer you want]
Equate the heat energy "lost" by this hot tea, to that gained by
1) the ice melting [latent heat]
2) the ice (now water) warming up from zero to T.
Do you know the formulas for heat lost/gained in terms of mass and latent heat; and mass, specific heat capacity and change in temperature?
BTW. The "m" will cancel out.Last edited by Stonebridge; 28-11-2010 at 14:39.