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    Can you help me with this

    I am seriously confused... Thanks

    \int_{1.5}^{0}\frac{dx}{\sqrt{9-x^2}}
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    You need a trig substitution.

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    x = 3 sin t
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    (Original post by asem93)
    Can you help me with this

    I am seriously confused... Thanks

    \int_{1.5}^{0}\frac{dx}{\sqrt{9-x^2}}
    As a hint, try differentiating arcsin x and see what you get.
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    There's a square root on the bottom that doesn't look nice, so look for a substitution to turn 9-x^2 into a square. :yep:

    Remember that the stuff in the square root is positive for real solutions, so x only takes values between -3 and 3 inclusive.
 
 
 
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