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# Projectiles Problem Watch

1. I have a test tomorrow and I try solving some questions we did in class but I couldn't get this one.

A ball is thrown upwards at 50deegres to the horizontal with an initial speed of 15m/s. Calculate the magnitude of its velocity when it is at its maximum height.

Any suggestions or solutions would be really helpful.
Thank you.
2. think of the maximum height as a maximum point.
i.e. where the vertical component of velocity is zero.
3. (Original post by TimmonaPortella)
think of the maximum height as a maximum point.
i.e. where the vertical component of velocity is zero.
so at the maximum point im gonna have to find the horizontal speed cz the vertical is 0?
4. (Original post by magos)
so at the maximum point im gonna have to find the horizontal speed cz the vertical is 0?
The horizontal component of the velocity stays constant throughout the trajectory, so if you can find it at the start from the info given, that's also the value at the maximum height. It's also the actual speed at the max height because all the velocity is horizontal there.
5. At it's maximum height the vertical component of it's velocity will be 0. So the magnitude will just be the horizontal component... I'm not telling you all the answers though, you can do that yourself

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